I’m new to electronics and would appreciate some guidance.
I’m trying to ‘hack’ a LED Fire-effect light bulb to work on a 9v battery to make it portable.
Using a multimeter I can see that the bulb converts mains voltage to 5v.
I’ve tried the following:
I’ve used a 5v LM7805 voltage regulator, this works well until the battery gets to around 6v which is below the regulator’s limit - causing the Circuit to stop with more than half the battery charge left.
I’ve used a MP1584EN buck converter, but have found that the voltage output doesn’t say a constant 5v as the battery drains - it looks like the converter fractions up the outgoing voltage (so if 5v is 55% of 9v, when the battery is at 6v the converter is delivering 3v)
Is there a way to get a constant 5v output from a 9v battery which uses up as much of the battery charge as possible? (I don’t want to be throwing away half-full batteries thinking they are empty)
Thanks for your help guys, and look forward to meeting you at your next open evening.